Question 726222
-2x^2+y^2+8x+6y-3=0
-2x^2+8x+y^2+6y-3=0
complete the square:
-2(x^2-4x+4)+(y^2+6y+9)=3-8+9
-2(x-2)^2+(y+3)^2=4
-2(x-2)^2+(y+3)^2=4
-(x-2)^2/2+(y+3)^2/4=1
{{{(y+3)^2/4-(x-2)^2/2=1}}}
This is an equation of a hyperbola with vertical transverse axis with center at (2,-3)
Its standard form: {{{(y-k)^2/a^2-(h-k)^2/b^2=1}}}, (h,k)=(x,y) coordinates of center