Question 63744
QUESTION


3x^2-2x-1>- (greater than or equal) 0


ANSWER:

Here we can use quadratic formula to solve the problem.



If the quadratic equation is  ax^2 + bx + c >-0,



then the solution is given by (please read the inequality as greater than or equal to)



{{{x > (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 






Now compare the given equation with the standard equation,

Then we have,

a=3

b= -2 

c= -1


Now input all these values in the formula.

Then it comes like this,


{{{x > (-(-2)+- sqrt( (-2)^2-4*3*(-1) ))/(2*3) }}}




{{{x > ((2)+- sqrt( 4+12 ))/6 }}} 




{{{x > ((2)+- sqrt( 16))/6 }}} 



{{{x > ( 2 +- 4 )/6 }}} 


==>  x> ( 2 + 4 ) / 6  or  x > (2 - 4)/6

==>   x > 6/6    or  x > -2/6

==>   x > 1   or  x > -1/6



Which is the solutuion for your question.



Hope you  understood.


Regards.


praseenakos@yahoo.co.in