Question 726158
D=RT
D=(R+300)5 SHUTTLE #2'
D=R(5+.5)
(R+300)5=R(5+.5)
5R+1500=R*5.5
5R+1500=5.5R
5R-5.5R=-1500
.5R=-1500
R=-1500/-.5
R=3000 MPH IS THE SPEED OF SHUTTLE #1.
D=3300*5
3000+300=3300 MPH FOR THE SPEED OF SHUTTLE #2.
D=16,500 MILE THEY WILL MEET.
PROOF:
16,500=3000*5.5
16,500=16,500