Question 725993
LET X, X+2 & X+4 BE THE 3 INTEGERS.
X+(X+2)+3(X+4)=X+58
X+X+2+3X+12=X=58
5X-X=58-2-12
4X=44
X=44/4
X=11 ANS. FOR THE SMALLER INTEGER.
11+2=13 ANS. FOR THE MIDDLE NUMBER.
11+4=15 ANS. FOR THE LARGEST INTEGER.
PROOF:
11+13+3*15=11+58
24+45=69
69=69