Question 725977
solve these functions in [0,2pi]
1-cos(x)=1
x=0
..
2-cos(x)=-sqrt3/2
cosx=-√3/2
x=5&#960;/6, 7&#960;/6 (in quadrants II and III where cos<0)
..
3-sin(x)-sqrt3cos(x)=0
sinx=&#8730;3cosx
sinx/cosx=&#8730;3
tanx=&#8730;3
x=&#960;/3, 4&#960;/3 (in quadrants I and III where tan>0)
..
4-sin(x)cos(x)=0
sinx=0
x=0,&#960;
or
cosx=0
x=&#960;/2, 3&#960;/2