Question 725674
What is an equation of a parabola with the given vertex and focus? 
vertex: (–2, 5); focus: (–2, 6)
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This is a parabola that opens upward.
Its basic form of equation: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex
axis of symmetry: x=-2
p=1 (distance above vertex on the axis of symmetry)
4p=4
Equation: (x+2)^2=4(y-5)