Question 725775
Log1/3(x2+x)-log1/3(x2-x)=-1
log1/3[(x^2+x)/(x^2-x)]=-1
convert to exponential form: base(1/3) raised to log of number(-1)=number((x^2+x)/(x^2-x)
(1/3)^-1=(x^2+x)/(x^2-x)
3=x(x+1)/x(x-1)
3x-3=x+1
2x=4x
x=2