Question 725615
1-i^34 divided by 3 square root -1 +5 
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(1-i^(34))/(3i + 5)
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Simplify the numerator:
i^34 = (i^4)^8*i^2 = 1^8*(-1) = -1
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Your Problem:
= (1-1)/(3i + 5)
= 0/(5+3i) 
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= 0
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Cheers,
Stan H.
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