Question 725503
What is the probability that a poker hand (5 card draw) contains nothing but aces and eights? 
-----
I'm assuming there are at least one ace and 1 eight in each hand.
--------------
Successful combinations in ace/8's order:
1/4 ; 2/3 ; 3/2 ; 4/1
-----
# of ways to get each combination:
1/4::: 4C1*4C4 = 4*1 = 4
2/3::: 4C2*4C3 = 7*4 = 28
3/2::: 4C3*4C2 = 4*7 = 28
4/1::: 4C4*4C1 = 1*4 = 4
Total number of 5 card hands with at least one ace and one eight: 64
====
Total number of 5 card hands: 52C5 = 2598960
Probability = 66/2598960 = 0.00002539
==========
Cheers,
Stan H.