Question 724909
Suppose that only 65% of all drivers in a certain state wear a seat belt. A random sample of 80 drivers is selected. What is the probability that more than forty-two drivers wear a seat belt?
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Binomial Problem with n = 80 and p(wear) = 0.65
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P(43<= x <=80) = 1 - binomcdf(80,0.65,42) = 0.9858
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Cheers,
Stan H.