<PRE><B>Question 725216</B>
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The perimeter of a rectangle is given by:  *[tex \LARGE P\ =\ 2l\ +\ 2w].  But since you know that the width is 8 feet less than the length:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2l\ +\ 2\left(l\ -\ 8\right)\ =\ 96]


Solve for *[tex \LARGE l].  Once you know the length, calculate *[tex \LARGE w\ =\ l\ -\ 8] to get the width and then calculate *[tex \LARGE l\ \times\ w] to get the area.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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