Question 63702
slope is (y2-y1)/(x2-x1)
(5-6)/(4-0)
-1/4 is the slope
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Y=mX+b
-4=-1/3*3+b
-4=-1+bB
b=-4+1
b=-3 THUS THE EQUATION OF THIS LINE IS
Y=-1/3X-3
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Y=4X+b OR
-4=4*1+b
-4=4+b
b=-8 THEN THE EQUATION OF THIS LINE & PERPENDICULAR TO ONE WITH A SLOPR OF 
(-1/4) IS
Y=4X-8