Question 724592
What are the focus and the directrix of the graph of x = 1/24y^2? 
y^2/24=x
y^2=24x
This is an equation of a parabola that opens rightward:
Its basic equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex
For given equation:
vertex:(0,0)
axis of symmetry: x-axis
4p=24
p=6
focus: (6,0) (p-distance to the right of the vertex on the axis of symmetry)
directrix: x=-6  (p-distance to the left of the vertex on the axis of symmetry)