Question 724412
I've tried to analyze this, and I believe it's a linear optimization problem, but intuition from facts in the problem description makes me think, put in as much gasoline into the moped as it can hold, 4 gallons, and put the remaining 10 gallons into the car.  That will give the most mileage possible with the 14 gallon allotment of gasoline.   


According to that, miles will be {{{100*4+30*10=700}}} miles.