Question 63647
Solve by graphing 
E1:  y=2x+3
E2:  x+y=3
:
For E1:
(I'm graphing this line by plotting points.)
Let x=0 and solve for y:
y=2(0)+3
y=0+3
y=3  Plot (0,3)
Now let x=2 and solve for y (Pick any point within reason.)
y=2(2)+3
y=4+3
y=7  Plot (2,7)
Connect the points and you should have this line:
{{{graph(300,200,-10,10,-10,10,2x+3)}}}
For E2:
(I'm graphing this line by the intercept method.)
Let x=0 and solve for y:
0+y=3
y=3  Plot (0,3) 
Notice that both lines have the same y-intercept.  This is the solution to the system.  (We're not supposed to know that yet, and most of the time we won't, so let's keep graphing.)
Let y=0 and solve for x:
x+0=3
x=3  Plot (3,0)
Connect the points and you have a second line:
{{{graph(300,200,-10,10,-10,10,2x+3,-x+3)}}}
The lines intersect at the solution: (0,3)
Happy Calculating!!!!