Question 63641
One number is 6 more than another.  If the sum of the smaller number and 3 times the larger number is 34, find the two numbers.
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Let S = the smaller number and L = the larger one.

Then, {{{S+3L=34}}} and {{{L=S+6}}}.
Replace L with S+6 in the first equation:

Then, {{{S+3(S+6)=34}}} or {{{S+3S+18=34}}}.
So, {{{4S=16}}} or {{{highlight(S=4)}}}.
So, the smaller number is 4. The larger is 6 more than 4 so the larger number = 10.

To verify that the numbers are 4 and 10 we note the the sum of the smaller number and three times the larger number is {{{4+3(10) = 4+30 = 34}}}.