Question 724202
Peter kayaked 1.0 x 10^6 meters at a rate of 6.0 x 10^3 meters per hour.
(That's the correct scientific notation way of expressing one million meters, and six thousand meters per hour, when the values are not known with enough precision to give more than two significant figures).
 
The number of hours Peter paddled is
{{{1.0*10^6/(6.0*10^3)=10*10^5/(6.0*10^3)=(10/6)*10^2=(5/3)*10^2=about 1.7*10^2=170}}} (rounded to the nearest 10)
 
NOTE: The answer {{{1.7*10^2}}} hours makes it clear that we know the answer with enough certainty to give two significant figures, while {{{170}}} would make us wonder if that last zero is significant. Since {{{1.0*10^6}}} meters and {{{6.0*10^3}}} meters per hour are given with only two significant figures, the result should have two significant figures.