Question 724019
Find the larger of the two consecutive odd integers if the larger is 40 less then three times the smaller.
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1st: 2x-1
2nd: 2x+1
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Equation:
2x+1 = 3x-40
x = 41
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2x-1 = 81
2x+1 = 83
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Cheers,
Stan H.
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