Question 723775
1	y  	=	2    	x		-3	
Divide by	1						
	y  	=	2    	x		-3    	
Compare this equation with y=mx+b							
slope m =	2    						
The slope of a line parallel to the above line will be the same							
The slope of the required line will be			2    				
m=	2    	,point	(	-5	,	3	)
Find b by plugging the values of m & the point in							
y=mx+b							
3	=	-10      	+	b			
b=	13						
m=	2    						
Plug value of  the slope  and b					in y = mx +b		
The required equation is   y  	=	2    	x	+	13  



1	y  	=	  1/ 2	x		-1    				
Divide by	1									
	y  	=	  1/ 2	x	+	-1    				
Compare this equation with y=mx+b,					m= slope & b= y intercept					
slope m =	 1/2									
										
The slope of a line perpendicular to the above line will be the negative reciprocal										-2    
Because m1*m2 =-1										
The slope of the required line will be			-2    							
										
m=	-2    	,point	(	2	,	4	)			
Find b by plugging the values of m & the point in										
y=mx+b										
4	=	-4      	+	b						
b=	8    									
m=	-2    									
The required equation is		y  	=	-2      	x	+	8      			






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