Question 723561
{{{3r^2+2r-2=0 }}}


/3

{{{r^2+(2/3)r-(2/3)=0}}}


{{{r^2+(2/3)r=(2/3)}}}

third term = (1/2 co efficient of middle term)^2


=((1/2) (2/3))^2

=1/9
{{{r^2+(2/3)r+(1/9) =(2/3)+(1/9)}}}


{{{r+(1/3))^2=(7/9)}}}

Take square root

r+(1/3) = +-sqrt(7)/3

r= (-1+sqrt(7))/3

OR

r=(-1-sqrt(7))/3