Question 8059
if you have log(x) to base a, and want it to base b, then its equivalent is:


log(x)/log(a) both to base b


eg ln 10 is the same as log10/log(e) where e is 2.71828


easy to remember...we had log(x)...we still have log(x) --> to the new base just divided by the "log of the base" bit.


Hope this helps


jon.