Question 723347
How to graph: f(x)=2log(base 2)(x+8)-3
Do it in steps:
log2(x):Basic log curve
asymptote at x=0 or y-axis
x-intercept at (1,0)
..
log(x+8): shift curve 8 units left
asymptote at x=-8
x-intercept at (-7,0)
..
log(x+8)-3: drop curve 3 units down
asymptote: no change at x=-8
x-intercept coordinates drop to (-7,3)
..
2log(base 2)(x+8)-3: slope increases slightly(final configuration)
asymptote: no change at x=-8
x-intercept coordinates remain at (-7,3)