Question 63413
Please help me to find these points if they exist, and if they don't please let me know. Thanks so much for your help I do appreciate it. 
6.f(x) = x – 3/x + 2 
PLEASE PUT BRACKETS...
THIS COULD MEAN (X)-(3/X)+2 OR (X)-3/(X+2) OR (X-3)/(X+2)
I AM TAKING IT AS F(X) = Y = (X-3)/(X+2)
x-intercepts 
WHERE Y =0?
Y=0 AT X=3...HENCE X INTERCEPT =3
y-intercepts 
WHERE X=0?
WHEN X=0,Y=-3/2
HENCE Y INTERCEPT = -3/2
Vertical asymptotes 
AT WHAT X VALUE Y TENDS TO INFINITY?
AS X TENDS TO -2...Y TENDS TO INFINITY ...
HENCE X = - 2 IS THE VERTICAL ASYMPTOTE. 
Horizontal asymptotes 
WHAT IS THE LIMIT OF Y AS X TENDS TO INFINITY?
Y =[1-(3/X)]/[[1+(2/X)]...AS X TENDS TO INFINITY ...Y TEND TO 1.
HENCE Y=1 IS THE HORIZONTAL ASYMPTOTE. 
Domain of the function 
IS THE PERMISSIBLE VALUES OF X WHICH MAKES THE FUNCTION DEFINABLE
AT X=-2 , THE FUNCTION IS NOT DEFINED AS DIVISION BY ZERO IS NOT ADMISSIBLE.
HENCE DOMAIN IS ALL REAL VALUES OF X EXCEPT -2
THAT IS (-INFINITY,-2)U(-2,INFINITY) 


6.g(x) = 3x^2/x^2 + x - 6
SAME AS ABOVE..PUT BRACKETS..ASSUMING IT IS 
3X^2/(X^2+X-6) IT IS Y=3X^2/(X+3)(X-2)
HOPE YOU CAN CONTINUE A ABOVE NOW.IF STILL IN DIFFICULTY PLEASE COME BACK
x-intercepts 
y-intercepts 
Vertical asymptotes 
Horizontal asymptotes 
Domain of the function