Question 63580
QUESTION:

Solve for x: log(4x + 8) - log 2=1


ANSWER:


Use  law of logarithm,


log A - logB = log(a/B)



Also here we can take, 

1= log 10, because, value of log 10 to the base10 is 1


so,   log(4x + 8) - log 2=1



==>   log(4x + 8) - log 2=log 10



==>   log{(4x + 8)/2 }= log 10



Both side we have logarithm, so,




==>  4x + 8)/2 = 10



==>  4x + 8 = 10 * 2


==>  4x + 8 = 20


==> 4x = 20 - 8


==> 4x = 12


==> x = 12/4



==> x = 3



Hope you understood.


Regards,

praseenakos@yahoo.co.in