Question 63579
ANSWER:


Write as a single logarithm: log 12 + log (x-2) - log 2. 
I thought that I might have to turn it into exponetial form first but Im not sure.

ANSWER:



LAWS OF LOGARITHM:



 logA + logB = log AB

log A - log B = log (A/B)





So,        log 12 + log (x-2)       =   log {12 * (x-2)}

                                    =   log {12(x-2)}



 so,   log 12 + log (x-2) - log 2   =  log {12(x-2)} - log 2


                                    =  log {12(x-2)/2}


                                    =  log {6(x-2)}


                                    =  log {6x- 12}



Hope you understood.


Regards,

praseenakos@yahoo.co.in