Question 722981
gerald had scores of 80,92,89,and 95 on four exams in his algebra class. what score will he need on his fifth exam to have an overall average of 90
----
Let the 5th exam score be "x":
(80+92+89+95+x)/5 = 90
---
356+x = 450
x = 94
===========
Cheers,
Stan H.
=============