Question 63548
QUESTION;

Find the slope of given equations.


ANSWER;


The equation of the line can be written in slope-intercept form as

 y = mx+b where 'm' is the slope of the equation and b is the 'y' intercept.

To find the slope of the equation, first of all rewrite the given equation in standard form,  that is  y = mx + c



1.3x+5y=1


==>3x+5y=1

Subtract 3x from both sides of the equation,

==> 3x + 5y -3x = 1-3x

==> 5y = 1-3x


Divide both sides by 5

==> 5y/5 = ( 1-3x )/5

==>  y = 1/5 - 3x/5

==>  y = 1/5 + (-3/5)x

==>  y = (-3/5)x + 1/5, which  is of the form, y = mx + c

where m = -3/5

Therefore slope of the equation is -3/5




2. 4x - 5y = 2

As in above proceed,

4x - 5y -4x = 2 -4x

==> -5y = 2- 4x

==> -5y/-5 =(2-4x)/-5

==>  y = 2/-5 - 4x/-5

==>  y = (-2/5) + (4/5)x 


==>  y = (4/5)x + ( -2/5)

which is of the form, y = mx +c

so here slope is = 4/5




3.   2x +3y +5 = 0

     2x + 3y + 5 - 5 = 0 - 5

2x + 3y = -5

2x + 3y - 2x = -5 -  2x

3y = -5 - 2x 

3y/3 = -5/3 -2x/3

y = (-5/3) + ( -2/3)x

Therefore, slope = (-2/3)

Regards.

praseenakos@yahoo.co.in