<PRE><B>Question 722706</B>
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I cannot emphasize this strongly enough:  &lt;b&gt;&lt;i&gt;&lt;font size=&quot;+3&quot;&gt;You cannot, under any circumstances, divide by zero!&lt;font size=&quot;+2&quot;&gt;&lt;/i&gt;&lt;/b&gt;


Now, assuming that the *[tex \LARGE -\ 96y] in your original is a typo and you really meant *[tex \LARGE -\ 96x], then everything &lt;b&gt;&lt;i&gt;else&lt;/i&gt;&lt;/b&gt; you did was correct.  You should have obtained:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 16(x\ -\ 3)^2\ -\ 9y^2\ =\ 0]


This is a degenerate hyperbola, in other words two intersecting straight lines.  The &quot;center&quot; is the point of intersection.  There are no vertices or foci, and the lines themselves &lt;b&gt;&lt;i&gt;would be&lt;/i&gt;&lt;/b&gt; the asymptotes if the RHS of your equation were other than zero.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 16(x\ -\ 3)^2\ =\ 9y^2]


Take the square root of both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4(x\ -\ 3)\ =\ \pm3y]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ -\ 12\ =\ \pm3y]


Which are the two straight lines:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ +\ 3y\ =\ 12]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ -\ 3y\ =\ 12]


Which intersect at *[tex \LARGE (3,0)]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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