Question 722730
Write an equation of the line containing the given point and perpendicular to the given line. 
(0,9); 2x + 9y = 8
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Equation of a line: y=mx+b, m=slope, b=y-intercept
2x+9y=8
9y=-2x+8
y=(-2/9)x+8
slope,m=-(2/9)
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slope of line perpendicular to given line=9/2 (negative reciprocal)
Equation of perpendicular line: y=(9/2)x+b
solving for b using coordinates of given point (0,9)
9=(9/2)*0+b
b=9
Equation of perpendicular line: y=9x/2+9