Question 722531
x1	y1	x2	y2									
-5      	3    	5    	-2    									
												
The general equation of the line when co-ordinates of two points are given is												
												
{{{(y-	y1)/(	y1-y2) = (x-x1)/(x1-x2)}}}										
												
{{{(y-	3    	)/(	3    	-	-2    	)=(x-	-5      	)/(	-5    	-	5    	)}}}
												
												
{{{(y-	-3      	)/(	5      	)=(x+	5      	) /(	-10      	)}}}				
												
{{{ 	-10      	(y-	-3      	) =	5      	(x-	-5      	)}}}				
												
-10      	y-	30      	=	5      	x  	-25      						
												
-10      	y=	5      	x+	5      								
/	-10      											
y=	-  1/ 2	x	-  1/ 2								
				

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slope 8, (5,42)

Point slope form of equation

y-y1=m(x-x1)

y-42=8(x-5)	

y-42=8x-40

y=8x+2