<PRE><B>Question 722111</B>
---	percent	----------------	Amount									
Alcool I	20	----------------			3	gal						
Alcohol II	70	----------------			x	gal						
Mixture	40	----------------	3	+	x	gal						
												
20	*	3	+	70	x	=	40	(	3	+	x	)
60	+	70	x	=	120	+	40	x				
70	x		-40	x	=	-60	+	120				
30	x	=	60									
/	30											
x	=	2		gal	Alcohol II							
												
m.ananth@hotmail.ca												
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