Question 721914
the vertex form equation for a parabola 

{{{y-k = a(x-h)^2}}} -- {{{vertical}}} parabola

{{{x-h = a(y-k)^2}}} -- {{{horizontal}}} parabola


for {{{vertical}}} parabola:

If {{{a> 0}}}, the parabola opens {{{up}}}
            if {{{a< 0}}}, it opens {{{down}}}


for {{{horizontal}}}  parabola:
If {{{a> 0}}}, the parabola opens {{{right}}}
            if {{{a< 0}}}, it opens {{{left}}}



in your case we have:


{{{ y-3=(x+2)^2 }}}...{{{vertical}}} parabola...{{{a=1}}},so {{{a>0}}} and the vertex is is (-2,3) and it opens {{{up}}}


.{{{ x-3=-(y+2)^2 }}} ..{{{horizontal}}}  parabola...{{{a=1}}}, so {{{a<0}}}, the vertex is is (3,-2) and it opens {{{left}}}


{{{ y-3=-(x+2)^2 }}}..{{{vertical}}} parabola...{{{a<0}}}, the vertex is is (-2,3) and it opens {{{down}}}


{{{ x-3= (y+2)^2 }}}..{{{horizontal}}}  parabola...{{{a>0}}}, the vertex is is (3,-2) and it opens {{{right}}}