Question 721931
A chemist has 40 ounces of a solution of iodine and alcohol that is 15% iodine. How much pure iodine must be added to make a solution that is 20% iodine?
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let x=pure iodine to be added
15%*40+100%x=20%(40+x)
6+x=8+.2x
.8x=2
x=2.5
pure iodine to be added=2.5 oz