Question 721902
how do you graph y = (x + 3)^2 - 2
This is an equation of a parabola. 
Its standard form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex
For given equation:y = (x + 3)^2 - 2
Vertex: (-3,-2)
Since lead coefficient >0, parabola opens upward 
y-intercept
set x=0
y=9-2=7
x-intercepts
set y=0
(x+3)^2=2
x+3=±√2
x=-3±√2
You now have enough information to graph given equation
See graph below as a visual check:

{{{ graph( 300, 300, -10, 10, -10, 10, (x + 3)^2 - 2) }}}