Question 63391
x^2-x-6/2x^2-13x+21
:
You can factor both the numerator and the denominator
{{{(x^2-x-6)/(2x^2-13x+21)}}} = {{{((x-3)(x+2))/((2x-7)(x-3))}}}
:
you can cancel the (x-3)'s and you have
{{{(x+2)/(2x-7)}}}