Question 721757
Do you find a need to do any operation with the grouped terms of the third number?  I see none.  The grouping symbols only help you to identify this expression of the third number.  You may then remove those grouping symbols and proceed to combine like terms of "a".  


{{{a+3a+(a/2+60)=1032}}}
{{{a+3a+a/2+60=1032}}}
{{{(1+3+1/2)a+60=1032}}}
I show the a there as factored from the terms of a, since you have a bit of conventional fraction work to do for combining the like terms of a.  You continue from here.