Question 721679
With this kind of problem, what they want you to
do is set up 2 equations and solve by some
means- elimination, substitution, etc.
Let {{{ s }}} = the cost of a student ticket
Let {{{ a }}} = the cost of an adult ticket
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(1) {{{ 13s + 7a = 134 }}}
(2) {{{ 10s + 6a= 108 }}}
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Multiply both sides of (1) by {{{ 10 }}}
Multiply both sides of (2) by {{{ 13 }}}
Then subtract (1) from (2)
(2) {{{ 130s + 78a = 1404 }}}
(3) {{{ -130s - 70a = -1340 }}}
{{{ 8a = 64 }}}
{{{ a = 8 }}}
and, since
(2) {{{ 10s + 6a= 108 }}}
(2) {{{ 5s + 3*8 = 54 }}}
(2) {{{ 5s = 54 - 24 }}}
(2) {{{ 5s = 30 }}}
(2) {{{ s = 6 }}}
The cost of a student ticket is $6
The cost of an adult ticket is $8
check:
(1) {{{ 13s + 7a = 134 }}}
(1) {{{ 13*6 + 7*8 = 134 }}}
(1) {{{ 78 + 56 = 134 }}}
(1) {{{ 134 = 134 }}}
OK