Question 721351
{{{log(4,(x + 3)) + log(4, (x - 3)) = 2}}}....in base {{{10}}} it will be


{{{log((x + 3))/log(4) + log((x - 3))/log(4) = 2}}}



{{{(log((x + 3)) + log((x - 3)))/log(4) = 2}}}


{{{log(((x + 3)(x - 3))) = 2log(4)}}}


{{{log(((x + 3)(x - 3))) = log((4^2))}}}


{{{log(((x + 3)(x - 3))) = log(16)}}}...if log same, then 


{{{(x + 3)(x - 3) = 16}}}....solve for {{{x}}}


{{{x^2 - 9 = 16}}}


{{{x^2  = 16+9}}}


{{{x^2  = 25}}}


{{{x = sqrt(25)}}}


{{{x = 5}}}