<PRE><B>Question 721304</B>
Please help me solve this. Let f(x)=3x^2-4 and g(x)=x^2-3x-4. Find each of the following. 
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A) (f+g)(2k) = f(2k) + g(2k) = [3(2k)^2-4] + [(2k)^2-3(2k)-4]
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= 12k^2 - 4 + 4k^2 - 6k -4
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= 16k^2 -6k - 8
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B)(f/g)(-1) = f(-1)/g(-1) = [3(-1)^2-4]/[(-1)^2 -3(-1)-4]
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= [3-4]/[1+4-4
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= -1/1
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= -1
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Cheers,
Stan H.
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