Question 721159
(2,8)(6,14)

mid point 
x= (6+2)/2=4
y=(14+8)/2= 11

Mid point(4,11)

Distance between two points													
x1	y1	x2	y2										
													
2	8	6	14										
d=	{{{sqrt((y2-y1)^2+(x2-x1)^2)}}}												
d=	{{{sqrt((		14	-	8	)^2	+	(	6	-	2	)^2	)}}}
d=	{{{sqrt((		6	)^2	+	(	4	)^2	)}}}				
d=	{{{sqrt((		52	)  	)}}}								
d=	7.21		

follow same steps for others										
m.ananth@hotmail.ca