Question 721043
{{{(x^2+2xy+y2)/(x/y-y/x)}}}={{{(x^2+2xy+y2)/(x^2/xy-y^2/xy)}}}={{{(x^2+2xy+y2)/((x^2-y^2)/xy)}}}={{{(x+y)^2/(((x+y)(x-y))/xy)}}}={{{(x+y)^2*(xy/((x+y)(x-y)))=xy(x+y)/(x-y)}}}