<PRE><B>Question 720981</B>
The perimeter of a triangle is the sum of the side lengths.  The distance formula gives the distance between points on a coordinate plane.  The distance between pairs of points (vertices) in a triangle is the side length.&lt;P&gt;
The distance formula is the square root of the difference between the y values squared plus the difference between the x values squared.&lt;P&gt;
d={{{sqrt((y(2)-y(1))^2 + (x(2)-x(1))^2)}}}&lt;P&gt;
The triangle has three sides: QR, RS and SQ.  Find the lengths of those sides, then add them to find the perimeter.&lt;P&gt;
QR length = d = {{{sqrt((1-6)^2 + (-3-2)^2) = sqrt(50)}}}&lt;P&gt;
RS length = d = {{{sqrt((2-1)^2 + (6-(-3))^2) = sqrt(82)}}}&lt;P&gt;
SQ length = d = {{{sqrt((6-2)^2 + (2-6)^2) = sqrt(32)}}}&lt;P&gt;
Their sum is approximately 21.78

&lt;P&gt;Hope the solution helped.  Sometimes you need more than a solution.  Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.)</PRE>