Question 63505
If at all possible factorise the terms. If you are lucky then a factor on the top of the division may cancel out one on the bottom of the division. The factors on the bottom cannot equal zero.
{{{(3x-15)/(x^2-7x+10)}}}
{{{3(x-5)/((x-5)(x-2))}}}
ie x cannot be 5 or 2
Cancel the (x-5) factor to get
{{{3/(x-2)}}}