Question 720748
{{{ (2c^2*d^0)^3*(5c^7*d^2) }}}
Anything to the zero power is {{{ 1 }}},
so I can rewrite as:
{{{ (2c^2*1)^3*(5c^7*d^2) }}}
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Use the general rule:
{{{ ( a^b )^c = a^(b*c) }}}
{{{  2^3*c^(2*3) * (5c^7*d^2) }}}
{{{  2^3*c^6 *5c^7*d^2 }}}
Now just reorder these factors
{{{ 8*5*c^6*c^7*d^2 }}}
{{{ 40*c^6*c^7*d^2 }}}
Use the general rule:
{{{ a^b * a^c = a^( b+c ) }}}
{{{ 40*c^( 6 + 7 ) *d^2 }}}
{{{ 40c^13*d^2 }}}
Hope I got it