Question 720732
recall that {{{1}}} degree={{{60}}}', and {{{1}}}'={{{60}}}"

a. {{{21}}} degrees {{{35}}}' {{{31}}}" + {{{49}}} degrees {{{51}}}' {{{32}}}"...add degrees and degrees, min and min, sec and sec

({{{21}}} degrees+ {{{49}}} degrees)+ ({{{35}}}'  + {{{51}}}')+({{{31}}}"+{{{32}}}")


{{{70}}} degrees {{{86}}}' {{{63}}}"....note that you have {{{86}}}' and it is equal to {{{1}}} degree and  {{{26}}}'...so; add {{{1}}} degree to {{{70}}} degrees

{{{71}}} degrees {{{26}}}'{{{63}}}"....note that you have {{{63}}}" and it is equal to {{{1}}}' and {{{3}}}"..so; add {{{1}}}' to min 

{{{71}}} degrees {{{27}}}'{{{3}}}"



b. {{{93}}} degrees {{{38}}}' {{{14}}}" - {{{13}}} degrees {{{49}}}' {{{27}}}"

subtract  degrees from degrees, min from min, sec from sec

{{{93-13}}} degrees {{{38-49}}}' {{{14-27}}}" 

{{{80}}} degrees {{{38-49}}}' {{{14-27}}}" ...as you can see, you cannot subtract {{{38-49}}}', so you borrow {{{1}}} degree from {{{80}}} degrees and convert it in min and add to {{{38}}}'

{{{79}}} degrees {{{98-49}}}' {{{14-27}}}"

{{{79}}} degrees {{{49}}}' {{{14-27}}}"....you cannot subtract {{{14-27}}}", so you borrow {{{1}}}' convert it in sec and add to {{{14}}}"


{{{79}}} degrees {{{48}}}' {{{74-27}}}"


{{{79}}} degrees {{{48}}}' {{{47}}}"





Express the following in degrees, minutes and seconds without decimals:
a. {{{10.3}}} degrees ={{{10}}} degrees{{{0.3*60}}}' ={{{10}}} degrees{{{18}}}'

b. {{{15.14}}} degrees 
={{{15}}} degrees{{{0.14*60}}}'
={{{15}}} degrees{{{8.4}}}'
={{{15}}} degrees{{{8}}}'{{{0.4*60}}}"
={{{15}}} degrees{{{8}}}'{{{24}}}"