Question 720419
{{{x^3y^(-3)/(xy)^(-1)}}}
We start with the denominator. Using the {{{(ab)^n = a^n*b^n}}} rule we get:
{{{x^3y^(-3)/(x^(-1)y^(-1))}}}
Next we use the rule, {{{a^m/a^n = a^(m-n)}}}, we get:
{{{x^(3-(-1))y^(-3-(-1))}}}
which simplifies to:
{{{x^4y^(-2)}}}