Question 720607
You can think of the jogger as standing still and
the cyclist approaching at the sum of their speeds
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The jogger cuts down the distance between them by
{{{ d[1] = 6*1 }}}
{{{ d[1] = 6 }}} mi
So now the cyclist only has to travel {{{ 15 - 6 = 9 }}} mi
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Let {{{ t }}} = the time in hrs it takes the cyclist to meet the jogger
{{{ 9 = ( 6 + 9 )*t }}}
{{{ 9 = 15t }}}
{{{ 3 = 5t }}}
{{{ t = 3/5 }}} hrs
{{{ (3/5)*60 = 36 }}} min
The two will meet at 8:36 AM
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check:
jogger's equation:
{{{ d[2] = 6*(3/5) }}}
{{{ d[2] = 18/5 }}} mi
Cyclist's equation:
{{{ d[3] = 9*(3/5) }}}
{{{ d[3] = 27/5 }}}
{{{ d[2] + d[3] }}} must = 9 mi
{{{ 18/5 + 27/5 = 45/5 }}}
{{{ 45/5 = 9 }}}
OK