Question 720254
if you have this:

{{{1/6 - (2/3)m > 1/4}}}

{{{ - (2/3)m > 1/4-1/6}}}

{{{ - (2/3)m > (3*1)/(3*4)-(2*1)/(2*6)}}}


{{{ - (2/3)m > 3/12-2/12}}}

{{{ - (2/3)m > 1/12}}}

{{{ m > (1/12)/(-2/3)}}}

{{{ m <-(1*3)/(12*2)}}}

{{{ m <-cross(3)*1/(cross(12)4*2)}}}

{{{ m <-1/(4*2)}}}

{{{ m <-1/8}}}

({{{-infinity<m<-1/8}}})