Question 720177
Assume you mean
3|y+3| < 9
Divide both sides by 3 and you have
|y + 3| < 3
Two solutions
y + 3 < 3
y < 3 - 3
y < 0
and
y + 3 > -3, note we reversed the inequality sign when we change to -3
y > -3 - 3
y > -6