Question 720137
 24x to the 14th power square rooted.
.
Looks like:
{{{sqrt(24x^14)}}}
we can break up the x's like this:
{{{sqrt(24x^7x^7)}}}
now, we can take "pairs" out from underneath the radical:
{{{x^7*sqrt(24)}}}
factoring the 24 to prime numbers:
{{{x^7*sqrt(2*2*2*3)}}}
now, take out one pair of 2's:
{{{2x^7*sqrt(2*3)}}}
final answer:
{{{2x^7*sqrt(6)}}}